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31x-x^2-198=0
We add all the numbers together, and all the variables
-1x^2+31x-198=0
a = -1; b = 31; c = -198;
Δ = b2-4ac
Δ = 312-4·(-1)·(-198)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-13}{2*-1}=\frac{-44}{-2} =+22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+13}{2*-1}=\frac{-18}{-2} =+9 $
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